Answered

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The current through a motor is 210 A. If a battery keeps a 12.0 V potential difference across the motor, what electric energy is delivered to the motor in 10.0 s?

Sagot :

Given:

the current through motor is

[tex]I=210\text{ A}[/tex]

The potential of the battery is

[tex]V=12\text{ V}[/tex]

The time is

[tex]t=10\text{ s}[/tex]

Required: the energy delivered to the motor in 10 sec is?

Explanation:

first, we calculate the power delivered to the motor.

The power is given by

[tex]P=VI[/tex]

Plugging all the values in the above relation, we get:

[tex]\begin{gathered} P=12\text{ V}\times210\text{ A} \\ P=2520\text{ watt} \end{gathered}[/tex]

The energy delivered to the motor is given by

[tex]E=Pt[/tex]

Plugging all the values in the above relation, we get:

[tex]\begin{gathered} E=2520\text{ w}\times10\text{ s} \\ E=25200\text{ J} \\ \end{gathered}[/tex]

Thus, the energy delivered to the motor is 25200 J.

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