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Sagot :
Given data
*The given frequency is
[tex]f_1_{}=1695\text{ MHz}=1695\times10^6\text{ Hz}[/tex]*The another given frequency is
[tex]f_2=2200\text{ MHz=}2200\times10^6\text{ Hz}[/tex]*The given speed of light is c = 3.0 × 10^8 m/s
(a)
The formula for the wavelength is given as
[tex]\lambda_1=\frac{c}{f_1}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \lambda_1=\frac{(3\times10^8)}{(1695\times10^6)^{}} \\ =0.176\text{ m} \end{gathered}[/tex]The another wavelength for the another frequency is calculated as
[tex]\begin{gathered} \lambda_2=\frac{c}{f_2} \\ =\frac{(3.0\times10^8)}{(2200\times10^6)} \\ =0.136\text{ m} \end{gathered}[/tex](b)
Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.
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