Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

I have this homework i need help with ?Part (a)

I Have This Homework I Need Help With Part A class=

Sagot :

Given that the mass of train is

[tex]m=\text{ }8.12\times10^6\text{ kg}[/tex]

The deceleration of the train is

[tex]\begin{gathered} a\text{ = -104 km/h} \\ =-104\times\frac{5}{18} \\ =\text{ -28.88 m/s} \end{gathered}[/tex]

The braking force can be calculated by the formula

[tex]F=ma[/tex]

Substituting the values, the braking force will be

[tex]\begin{gathered} F=8.12\times10^6\times(-28.88) \\ =2.348\times10^8\text{ N} \end{gathered}[/tex]

Thus, the braking force is 2.348 x 10^8 N.

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.