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What is the concentration if I have 450 mL of iron (II) chloride (FeCl2) solution that contains9.6 grams of iron (II) chloride solute?

Sagot :

Answer;

0.168M

Explanations:

The formula for calculating the concentration of the solution is expressed as:

[tex]concentration=\frac{mole}{volume}[/tex]

Determine the moles of iron(II) chloride

[tex]\begin{gathered} mole\text{ of FeCl}_2=\frac{9.6g}{126.751g\text{/}mol} \\ mole\text{ of FeCl}_2=0.0757moles \end{gathered}[/tex]

Given that volume is 0.45L, hence the concentration is expressed as:

[tex]\begin{gathered} concentration=\frac{0.0757}{0.45} \\ concentration=0.168M \end{gathered}[/tex]

Hence the concentration of the solution is 0.168M

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