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Sagot :
Let us first define the term molarity. Molarity is a way of expressing the concentration of a compound in solution and is defined as the number of moles per liter of solution.
We are given the molarity value, 1.00M, and the volume of the solution, 500 mL=0.5L. We can find the number of moles by clearing them from the following equation:
[tex]\begin{gathered} Molarity=\frac{MolesSolute}{Lsolution} \\ MolesSolute=Molarity\times Lsolution \end{gathered}[/tex]We replace the known data:
[tex]\begin{gathered} MolesSolute=1.00M\times0.5L \\ MolesSolute=1.00\frac{mol}{L}\times0.500L=0.500molC_{12}H_{22}O_{11} \end{gathered}[/tex]Now, the grams of sucralose are found by multiplying the moles found by the molar mass of sucralose, which is 342.3 g/mol:
[tex]gC_{12}H_{22}O_{11}=0.500molC_{12}H_{22}O_{11}\times\frac{342.3gC_{12}H_{22}O_{11}}{1molC_{12}H_{22}O_{11}}=171gC_{12}H_{22}O_{11}[/tex]The quantity of sucrose required will be 171 g of sucrose
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