Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The given system is
[tex]\mleft\{\begin{aligned}y=5x-3 \\ 3x-8y=24\end{aligned}\mright.[/tex]We can multiply the first equation by 8, then we sum and solve for x.
[tex]\mleft\{\begin{aligned}8y=40x-24 \\ 3x-8y=24\end{aligned}\rightarrow3x=40x\mright.[/tex]Then we, solve for x.
[tex]\begin{gathered} 40x-3x=0 \\ 27x=0 \\ x=\frac{0}{27}=0 \end{gathered}[/tex]Now we use this value to find y.
[tex]\begin{gathered} 3x-8y=24 \\ 3(0)-8y=24 \\ -8y=24 \\ y=\frac{24}{-8}=-3 \end{gathered}[/tex]Therefore, the solution of the system is x = 0 and y = -3.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
