At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

A bouncy ball is dropped such that the height of its first bounce is 6.25 feet and each successive bounce is 74% of the previous bounces height. What would be the height of the sixth bounce the ball

Sagot :

EXPLANATION

The heigth of the first bounce is 6.25 feet

Each successive bounce is 74% of the previous bounces height

For the first bounce, the ball hit a height of 6.25 feet

The first successive bounce = 74% of the previous bounce

The previous bounce = 6.25 feets

Hence, 74% x 6.25 = Next successive bounce

The next successive bounce = 74/100 x 6.25

The next succesive bounce = 0.74 x 6.25

= 4.625 feets

For the next successive bounce

The previous successive bounce = 4.625 feets

The next successive bounce = 74% x 4.625

The next successive bounce = 0.74 x 4.625

The second successive bounce = 3.4225 feets

For third successive

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.