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solve the polynomial in standard form1) y=(x-3)^2-3(x-4)

Sagot :

[tex]y=\mleft(x-3\mright)^2-3\mleft(x-4\mright)[/tex][tex]\begin{gathered} y=x^2-6x+9-3x+12 \\ \end{gathered}[/tex]

we reduce the equal terms and we obtain the answer is

[tex]y=x^2-9x+21[/tex]

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