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What are the center and the radius of the circle x2−2x+y2=0?A)The center is (1, 0), and the radius is 1.B) The center is (2, 0), and the radius is 2.C)The radius is 0, so the equation cannot represent a circle.D) The radius is negative, so the equation cannot represent a circle.

What Are The Center And The Radius Of The Circle X22xy20AThe Center Is 1 0 And The Radius Is 1B The Center Is 2 0 And The Radius Is 2CThe Radius Is 0 So The Equ class=

Sagot :

We want to know the center and the radius of the circle:

[tex]x^2-2x+y^2=0[/tex]

We remember that the equation of a circle is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

In this case, we complete the square by adding 1 and substracting 1:

[tex]\begin{gathered} x^2-2x+1+y^2-1=0 \\ x^2-2x+1+y^2=1 \\ \text{Factoring the first three terms, we obtain:} \\ (x-1)^2+y^2=1 \end{gathered}[/tex]

This means that the center is the point (1,0), and:

[tex]\text{Radius: }\sqrt[]{1}=1[/tex]

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