Answered

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Solve for x in x^3 = 64/27.

Sagot :

ANSWER

[tex]x\text{ = }\frac{4}{3}[/tex]

EXPLANATION

We have that:

[tex]x^3\text{ = }\frac{64}{27}[/tex]

64 and 27 are perfect cubes. This is because they are integers that can be gotten when another integer is raised to the third power or multiplies itself three times.

So, to get x, we can find the cube root of both sides:

[tex]\begin{gathered} \sqrt[3]{x^3}\text{ = }\sqrt[3]{\frac{64}{27}} \\ \Rightarrow\text{ x = }\sqrt[3]{\frac{4\cdot4\cdot4}{3\cdot3\cdot3}} \\ x\text{ = }\frac{4}{3} \end{gathered}[/tex]

That is the value of x.

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