Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Solve for x in x^3 = 64/27.

Sagot :

ANSWER

[tex]x\text{ = }\frac{4}{3}[/tex]

EXPLANATION

We have that:

[tex]x^3\text{ = }\frac{64}{27}[/tex]

64 and 27 are perfect cubes. This is because they are integers that can be gotten when another integer is raised to the third power or multiplies itself three times.

So, to get x, we can find the cube root of both sides:

[tex]\begin{gathered} \sqrt[3]{x^3}\text{ = }\sqrt[3]{\frac{64}{27}} \\ \Rightarrow\text{ x = }\sqrt[3]{\frac{4\cdot4\cdot4}{3\cdot3\cdot3}} \\ x\text{ = }\frac{4}{3} \end{gathered}[/tex]

That is the value of x.

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.