At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Explanation:
We determine the mass of NO2 from the mass of Pb(NO3)2:
m is the mass, M is the molar mass
[tex]\begin{gathered} m(NO2)\text{ = }\frac{m(Pb(NO3)2)}{M(Pb(NO3)2)}\text{ }\times\text{ }\frac{mol\text{ \lparen NO2\rparen}}{mol(Pb(NO3)2)}\text{ }\times\text{ M\lparen NO2\rparen} \\ \\ \text{ =}\frac{80}{331.2}\text{ }\times\frac{4}{2}\text{ }\times\text{ 46.0055} \\ \\ \text{ = 22.22g} \end{gathered}[/tex]Percent yield:
[tex]\begin{gathered} percent\text{ yield = }\frac{Actual\text{ yield}}{Theoretical\text{ yield}} \\ \\ \text{ =}\frac{21.3}{22.22} \\ \\ \text{ = 0.9586 }\times\text{ 100} \\ \\ \text{ = 95.86\%} \end{gathered}[/tex]Answer:
Percent yield = 95.86%
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
