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You randomly choose one of the chips without replacing the first chip you choose a second chip. Which question is different find both answers.

You Randomly Choose One Of The Chips Without Replacing The First Chip You Choose A Second Chip Which Question Is Different Find Both Answers class=

Sagot :

The probability of event A and event B is the product of the probability of A snd the probability of B given that A has happened. It is written as

P(A and B) = P(A) x P(BIA)

Considering the first option,

We know that

probability = number of favourable outcomes/total number of outcomes

The total number of outcomes is 6

The probability of choosing a 1, P(A) = 1/6

There are 2 blue chips and since the 1 that was chosen was not replaced, the total number of outcomes would be 5. Thus, the probability of choosing a blue chip given that a 1 has been chosen, P(BIA) is 2/5

Thus, the probability of of choosing a 1 and then a blue chip is

1/6 x 2/5 = 1/15

Considering the second option,

The probability of choosing a 1, P(A) = 1/6

there are 3 even numbers. The probability of choosing an even number given that a green chip has been chosen, P(BIA) = 3/5

Thus, the probability of choosing a 1 and then an even number is

1/6 x 3/5 = 1/10

Considering the third option,

The probability of choosing a green chip, P(A) = 1/6

there are 3 chips that are not red after the green chip has been chosen. The probability of choosing a chip that is not red given that a green chip has been chosen, P(BIA) = 3/5

Thus, the probability of choosing green chip and then an even number is

1/6 x 3/5 = 1/10

Considering the fourth option,

The probability of choosing a number less than 2 is , P(A) = 1/6

there are 3 chips that are even numbers. The probability of choosing a chip that is an even number given that a number less than 2 has has been chosen, P(BIA) = 3/5

Thus, the probability of choosing a number less than 2 and then an even number is

1/6 x 3/5 = 1/10

Thus, the only different option is the first one

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