Answered

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What is the factored form of this expression?x^3 + 27(32 – 3) (3 + 35 + 9)(1 + 3) (12 - 35 + 9)(2 + 3) (1 - 3.5 + 9)(t – 3)(x2 + 3r + 9

Sagot :

We have the following:

[tex]\begin{gathered} x^3+27 \\ x^3+3^3 \end{gathered}[/tex]

now,

[tex]x^3+y^3=\mleft(x+y\mright)\mleft(x^2-xy+y^2\mright)[/tex]

replacing:

[tex]x^3+3^3=\mleft(x+3\mright)\mleft(x^2-3x+9\mright)[/tex]

The answer is the secondo option

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