Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Answer
4.22 atm
Explanation
Given that:
The initial pressure, P₁ = 6.1 atm
The initial temperature, T₁ = 2.0 °C = (2.0 + 273.15 K) = 275.15 K
The final temperature, T₂ = -83.0 °C = (-83.0 + 273.15 K) = 190.15 K
What to find:
The final pressure, P₂ (atm) of the gas at 83.0 °C.
Step-by-step solution:
The relationship between pressure and temperature of gaseous subtance was decribed by Amonton's gas law.
Amonton's Law states that the pressure of an ideal gas varies directly with the absolute temperature when the volume of the sample is held constant.
Mathematically, we have:
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]Putting the values of the parameters into the formula, we have:
[tex]\begin{gathered} \frac{6.1\text{ }atm}{275.15\text{ }K}=\frac{P_2}{190.15\text{ }K} \\ \\ P_2=\frac{6.1atm\times190.15K}{275.15K} \\ \\ P_2=4.22\text{ }atm \end{gathered}[/tex]Thus, the final pressure, (atm) of the gas at 83.0 °C is 4.22 atm.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.