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19.Solve the inequality. Express your answer in the form of a graph and in interval notation. (x-3) / (x+6) ≤ 0

Sagot :

The inequality is given as,

[tex]\frac{x-3}{x+6}\leq0[/tex]

Note that the denominator can never be zero otherwise the rational function would become indeterminate. So we have to exclude the value at which the denominator,

[tex]\begin{gathered} x+6=0 \\ x=-6 \end{gathered}[/tex]

So the function is not defined at x = - 6.

Consider that the division of the numbers can be non-positive, only if exactly one of the numbers is non-positive.

So we have to obtain the interval in which one of the factors is positive and the other is negative.

CASE-1: When the numerator is positive and the denominator is negative,