Answered

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Can you please help me with this question D and E

Can You Please Help Me With This Question D And E class=

Sagot :

Solution

Part d

T= -2ºC, V=15 km/hr

We can convert to F and mi/h like this:

T= 1.8*(-2)+ 32= 28.4ºF

Ms= As/0.62= 15 km/hr /0.62= 24.19 mi/hr

Replacing we have:

[tex]WC=35.74+0.6215\cdot(28.4)-35.75(24.19^{0.16})+0.4275(28.4)(24.19^{0.16})[/tex]

Solving we got:

[tex]WC=35.74+17.651-59.519+20.213=14.08[/tex]

Rounded to one decimal we got:

14.1

Part e

T= 10ºC = 1.8(10)+ 32=50ºF

Ms = 34 km/hr

Ms= As/0.62= 34 km/hr/ 0.62= 54.84 mi/hr

Replacing we got:

[tex]WC=35.74+0.6215\cdot(50)-35.75\cdot(54.84^{0.16})+0.4275(50)(54.84^{0.16})[/tex][tex]WC=35.74+31.075-67.847+40.566=39.53[/tex]

Rounded to the nearest tenth we got:

39,5

Althought the reported temperature is 50 ºFahrenheit, because of wind it feels like 39.5 Fahrenheit

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