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Seniors at a high school are allowed to go off campus for lunch if they have a grade of A in all their classes or perfect attendance. An assistant principal in charge of academics knows that the probability of a randomly selected senior having A's in all their classes is 0.1. An assistant principal in charge of attendance knows that the probability of a randomly selected senior having perfect attendance is 0.16. The cafeteria staff know that the probability of a randomly selected senior being allowed to go off campus for lunch is 0.18. Use the addition rule of probability to find the probability that a randomly selected senior has all As and perfect attendance.

Sagot :

Given:

Probability a randomly selected senior has A = 0.1

Probability a randomly selected senior has a perfect attendance = 0.16

Probability a randomly selected senior is being allowed to go offf campus: P(A or B) = 0.18

Let's find the probability that a randomly selected senior has all As and a perfect attendance using addition rule for probability.

Apply the formula below:

P(A or B) = P(A) + P(B) - P(A and B)

Rewrite for P(A and B):

P(A and B) = P(A) + P(B) - P(A or B)

P(A and B) = 0.1 + 0.16 - 0.18

Therefore, the probability that a randomly selected senior has all As and perfect attendance is

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