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Sagot :
Given the pair of simultaneous equation;
[tex]\begin{gathered} -8x+3y=3 \\ 13x-3y=-18 \end{gathered}[/tex]We are going to use the method of elimination to solve this.
We will be eliminating the variable y first, since it has the same co-efficient in the two(2) equations.
Thus, we have:
[tex]\begin{gathered} -8x+13x=3-18 \\ 5x=-15 \\ x=-\frac{15}{5} \\ x=-3 \end{gathered}[/tex]To solve for y, we are going to substitute for x = -3 into any of the two(2) equations.
Thus, we have:
[tex]\begin{gathered} \text{from equation i}i) \\ 13x-3y=-18 \\ 13(-3)-3y=-18 \\ -39-3y=-18 \\ -3y=-18+39 \\ -3y=21 \\ y=-\frac{21}{3} \\ y=-7 \end{gathered}[/tex]
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