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Sagot :
Let x, y and z denote the weighs of car X, car Y and car Z, respectively.
We know that car X weighs 136 more than car Z, this can be express by the equation:
[tex]x=z+136[/tex]We also know that Y weighs 117 pounds more than car Z, this can be express as:
[tex]y=z+117[/tex]Finally, we know that the total weight of all the cars is 9439, then we have:
[tex]x+y+z=9439[/tex]Hence, we have the system of the equations:
[tex]\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}[/tex]To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:
[tex]\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}[/tex]Now that we have the value of z we plug it in the first two equations to find x and y:
[tex]\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}[/tex]Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.
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