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USE THE NORMAL CURVE TABLE TO DETERMINE THE PERCENT OF DATA SPECIFIED.A) TO THE LEFT OF z = 1.62B) BETWEEN z = -1.53 AND z = -1.82

Sagot :

SOLUTION:

Using a normal distribution table, we find that;

a. The area to the left of z = 1.62 is;

[tex]P(z<1.62)=0.9474[/tex]

b. The area between z = -1.53 and z = -1.82, this is;

[tex]P(-1.82
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