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The equation for the motion of an object with constant acceleration is d=vt+0.5at2where d is distance traveled in ft, v is starting velocity in ft/s, a is acceleration inft/s2, and t is time in seconds. A racecar begins with a velocity of 200 ft/s andaccelerates at 100 ft/s2.8Write an expression for the distance the car travels after t seconds.

Sagot :

Replacing the values in the equation, we have:

D(t) = (200 ft/s)*t + 0.5*(100 ft/s2)*t^2

D(t) = (200 ft/s)*t + (50 ft/s2)*t^2 (Multiplying)

The answer is:

D(t) = (200)*t + (50)*t^2 (Distance in ft)

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