Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

What is the slope of a this perpendicular line 0=-15-7x+3y? Explain?





Sagot :

put it into slope intercept form y=mx+b where m is slope

0=-15-7x+3y
subtract 3y from both sides
-3y=-7x-15
multiply both sides by -1
3y=7x+15
divide both sdies by 3
y=7/3x+5
slope is 7/3

to find a line perpendicular to it, the slope of the other line, when multiplied by this line, must equal -1, exg
1/2 and -2/1 are perpenicular
-1 and 1 are perpendicular

therefor the line perpendicular to it has a slope of -3/7, exg y=-3/7+3
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.