Answered

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Consider the following compound inequality. 2x+3_<5 or 4x+1>17A)Solve the inequality for x.B) Graph the compound inequality. C) Enter the solution in interval notation.

Consider The Following Compound Inequality 2x3lt5 Or 4x1gt17ASolve The Inequality For XB Graph The Compound Inequality C Enter The Solution In Interval Notation class=

Sagot :

step 1

Solve the first inequality

[tex]2x+3\leq5[/tex][tex]\begin{gathered} 2x\leq5-3 \\ 2x\leq2 \\ x\leq1 \end{gathered}[/tex]

the solution for the first inequality is the interval (-infinite,1]

step 2

Solve the second inequality

4x+1>17

4x>16

x>4

the solution for the second inequality is the interval (4, infinite)

therefore

the solution of the compound inequality is

(-infinite,1] U (4, infinite)

In a number line, the solution is

At x=1 is a closed circle and at x=4 is an open circle

View image JaliahY121224
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