Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Consider the following compound inequality. 2x+3_<5 or 4x+1>17A)Solve the inequality for x.B) Graph the compound inequality. C) Enter the solution in interval notation.

Consider The Following Compound Inequality 2x3lt5 Or 4x1gt17ASolve The Inequality For XB Graph The Compound Inequality C Enter The Solution In Interval Notation class=

Sagot :

step 1

Solve the first inequality

[tex]2x+3\leq5[/tex][tex]\begin{gathered} 2x\leq5-3 \\ 2x\leq2 \\ x\leq1 \end{gathered}[/tex]

the solution for the first inequality is the interval (-infinite,1]

step 2

Solve the second inequality

4x+1>17

4x>16

x>4

the solution for the second inequality is the interval (4, infinite)

therefore

the solution of the compound inequality is

(-infinite,1] U (4, infinite)

In a number line, the solution is

At x=1 is a closed circle and at x=4 is an open circle

View image JaliahY121224
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.