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3a + 9 > 21 or -2a +4 > 16

Sagot :

We will look at how to evaluate inequalities in terms of a number line solution.

We have the following two inequalities:

[tex]3a\text{ + 9 > 21 or -2a + 4 > 16}[/tex]

We will first solve each inequality separately for the variable ( a ) as follows:

[tex]\begin{gathered} 3a\text{ > 12 or -2a > 12} \\ \textcolor{#FF7968}{a}\text{\textcolor{#FF7968}{ > 4 or a < -6}} \end{gathered}[/tex]

Now we will plot the solution on a number line as follows:

View image HadjaZ69135
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