Answer:
[tex]y=2x-3\rightarrow Slope-intercept\text{ form}[/tex]
Step by step explanation:
As a first step to find the equation of the line, we need to calculate the slope.
The slope is represented by the following equation:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \text{where,} \\ \text{ (x}_1,y_1)and(x_2,y_2)_{}_{} \\ \text{are the points given} \end{gathered}[/tex]
Then, the slope of the line would be:
[tex]\begin{gathered} m=\frac{9-3}{6-3} \\ m=\frac{6}{3} \\ m=2 \end{gathered}[/tex]
Then, by the slope-point form of the line we can get slope-intercept form:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-3=2(x-3) \\ y=2x-6+3 \\ y=2x-3\rightarrow Slope-intercept\text{ form} \end{gathered}[/tex]