Answered

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how do I solve (-2+5i) (4-i) +(2-i)

Sagot :

Given:

[tex](-2+5i)(4-i)+(2-i)[/tex]

Using the distributive property for the multiplication then combine the like terms

so, the given expression will be:

Note: i² = -1

[tex]\begin{gathered} (-2+5i)(4-i)+(2-i) \\ =-2(4-i)+5i(4-i)+(2-i) \\ =-8+2i+20i-5i^2+2-i \\ =-8+2i+20i+5+2-i \\ =(-8+5+2)+(2i+20i-i) \\ =-1+21i \end{gathered}[/tex]

So, the answer will be:

[tex]-1+21i[/tex]

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