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What is the solution to the equation below? Round your answer to two decimal places.ln x = 0.2A.x = 1.58B.x = -0.70C.x = -1.61D.x = 1.22

What Is The Solution To The Equation Below Round Your Answer To Two Decimal Placesln X 02Ax 158Bx 070Cx 161Dx 122 class=

Sagot :

Given the equation:

[tex]\ln \left(x\right)=0.2[/tex]

Apply the properties of logarithms:

[tex]e^{ln(x)}=e^{0.2}[/tex]

Simplify:

[tex]x=e^{0.2}=1.22[/tex]

Answer: D. x = 1.22