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5.Find the measures of themissing side of the righttriangle usingPythagorean Theoremequation.106K

Sagot :

Pythagoras Theorem:

In a right angle triangle, the sum of square of base and perpendicular is equal to the square of Hypotenuse .

Hypotenuse² = Perpendicular² + base²

In the given figure, we have:

Base = k

Hypotenuse = 10

Perpendicular = 6

Substitute the valus and solve for k,

[tex]\begin{gathered} \text{Hypotenuse}^2=Perpendicular^2+Base^2 \\ 10^2=6^2+k^2 \\ 100=36+k^2 \\ k^2=100-36 \\ k^2=64 \\ k=\sqrt[]{64} \\ k=8 \\ \text{Base, k = 8} \end{gathered}[/tex]

The missing side is 8

Answer: 8

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