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Line AB is perpendicular to line AC, line CD is congruent to line CE and measurement of angle B is 48° find measurement of angle DEB

Line AB Is Perpendicular To Line AC Line CD Is Congruent To Line CE And Measurement Of Angle B Is 48 Find Measurement Of Angle DEB class=

Sagot :

The sum of the interior angles of a triangle adds up to 180°.

Based on this, we can do the following...

0. Finding m∠C:

[tex]m\angle C+m\angle B+m\angle A=180[/tex][tex]m\angle C=180-m\angle B-m\angle A[/tex]

With the description of the problem, we know that m∠B = 48° and m∠A = 90°. Replacing these values:

[tex]m\angle C=180-48-90[/tex][tex]m\angle C=42[/tex]

With this angle and based on the same logic that the addition of the interior angles of a circle adds up 180°, we can get m∠CED. Also, as CD is congruent to CE, m∠CED = m∠CDE.

[tex]m\angle C+m\angle CED+m\angle CDE=180[/tex][tex]m\angle C+m\angle CED+m\angle CED=180[/tex][tex]m\angle C+2m\angle CED=180[/tex][tex]m\angle CED=\frac{(180-m\angle C)}{2}[/tex]

Replacing the value of m∠C previously calculated:

[tex]m\angle CED=\frac{(180-42)}{2}=\frac{138}{2}[/tex][tex]m\angle CED=69[/tex]

Finally, as we know segment CB is a straight line, the angle is 180°. Thus...

[tex]m\angle DEB+m\angle CED=180[/tex][tex]m\angle DEB=180-m\angle CED[/tex]

Replacing the value previously calculated:

[tex]m\angle DEB=180-69[/tex]

Answer:

[tex]m\angle DEB=111[/tex]

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