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The slope of the line below is -1/7. - Write a point-slope equation of the line using the coordinates of the labeled point. 10+ (3,3) - 10 110 - 10+ A. y+3 =-;(x +3) y-3--}(x-3) O C. y+3+7(x+3) O D. y-3 - (x-3)

The Slope Of The Line Below Is 17 Write A Pointslope Equation Of The Line Using The Coordinates Of The Labeled Point 10 33 10 110 10 A Y3 X 3 Y3x3 O C Y37x3 O D class=

Sagot :

Point slope formula:

y-y1 = m (x-x1)

Where:

m= slope

(x1,y1) = point of the line

Replacing with the point given (3.3) and slope =-1/7

y+3 = -1/7 (x+3)

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