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What is the axis of symmetry for f(x) = x2 + 4x + 6? A. x= -4B. X= -2C. X = 2D X = 3

Sagot :

Answer:

Step by step explanation:

In order to find the axis of symmetry, we will have to find the x-value of the vertex

[tex]\text{Vertex = }\lbrack\frac{-b}{2a},\text{ f(}\frac{-b}{2a})\rbrack[/tex][tex]x^2\text{ + 4x +6}[/tex]

a = 1

b = 4

c = 6

[tex]\text{Vertex = }\lbrack\frac{-4}{2},f(\frac{-4}{2})\rbrack[/tex][tex]Vertex=\lbrack-2,f(-2)\rbrack\text{ }[/tex]

We have found the x-value of the vertex which is -2

Line/axis of symmetry is x=-2

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