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solve the system x+3y=62x+4y=12

Sagot :

x+3y=6 ----------------------------(1)

2x+4y=12​---------------------------(2)

Using elimination method to solve;

we will eliminate x variable

To do that, we must make sure the coefficient of x in the two equation are the same.

This can be achieved by multiplying equation (1) by 2 and equation (2) by 1

That is;

2x + 6y = 12 ----------------------(3)

2x + 4y = 12 -----------------------(4)

subtract equation (4) from equation (3)

2y = 0

Divide both-side of the equation by 2

y=0

substitute y = 0 into equation (1)

x + 3(0) = 6

x = 6