Answered

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A4 resistor is connected to a 12-V battery. What is thecurrent through the battery? What is the power dissipatedby the resistor?

Sagot :

According to Ohm's law,

So the current is given as,

The power dissipated by the resistor is given as,

Hence, 3 A of current passes through the resistor and power dissipated is 36 W.

[tex]\begin{gathered} P=I^2R \\ =(3A)^2\times4\text{ }\Omega \\ =36\text{ W} \end{gathered}[/tex]

[tex]\begin{gathered} I=\frac{V}{R} \\ I=\frac{12\text{ V}}{4\text{ }\Omega} \\ I=3\text{ A} \end{gathered}[/tex]

[tex]V=IR[/tex]

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