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what is the center and radius for the circle with equation (x-2)^2 + (y-5)^2=49

Sagot :

Solution

For this case we have the following equation given by:

[tex](x-2)^2+(y-5)^2=49[/tex]

The general equation of a circle is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

And for this case by direct comparison we have:

[tex]r^2=49[/tex]

Then we have:

[tex]r=\sqrt[]{49}=7[/tex]

And the center si given by C=(h,k)

From the equation given we have:

[tex]C=(2,5)[/tex]

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