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Sagot :
system equation is
y = 2x - 2
-4x - y = 26
we will be solving this equation simultaneously by using substitution method
y = 2x - 2 --------- equation 1
-4x - y = 26 ------- equation 2
substiute y = 2x - 2 into equation 2
equation 2 becomes
-4x - (2x - 2) = 26
-4x - 2x + 2 = 26
collect the like terms
-4x -2x = 26 - 2
x(-4 - 2) = 24
x(-6) = 24
-6x = 24
to find x, divide both sides by -6
-6x/-6 = 24/-6
x = 24/-6
x = -4
to find y put x = -4 into equation 2
-4x - y = 26
-4(-4) - y = 26
16 - y = 26
collect the like terms
-y = 26 - 16
-y = 10
divide both sides by -1
-y/-1 = 10/-1
y = -10
the answer is x= -4 and y = -10
Using elimination method for the following equation
5x + y = 24
-5x - 4y = -56
in elimination method, you need to eliminate one of the variables before you can get the other variable
so let us eliminate x first
5x + y = 24
-5x -4y = - 56
since the second equation have a negative value of 5x then, we need to sum up the two equations to eliminate x
5x + (-5x) + y +(-4y) = 24 + (-56)
0x + y - 4y = 24 -56
-3y = -32
divide both sides by -3
-3y / -3 = -32/-3
y = 32/3
The answer is 32/3
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