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1. What is the molarity of a solution of HNO3 that contains 25.2 g of HNO3 in 1.0 L of solution?

Sagot :

Explanation:

First, let's discover the quantity in moles of 25.2 g of HNO3. For this, we use the following formula: n = m/MM

MM of HNO3 = 63 g/mol

m = 25.2

n = 25.2/63

n = 0.4 moles

Now using the following formula: M = n/V

We can find the molarity of the solution:

n = 0.4 moles

V = 1L

M = 0.4/1

M = 0.4 mol/L

Answer: 0.4 mol/L