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Sagot :
Answer:[tex]\text{Each smaller piece has a width of 5}\frac{3}{4}\text{inches}[/tex]Explanations:
The total width of each piece of paper:
[tex]\begin{gathered} W\text{ = 11}\frac{1}{2}\text{inches} \\ W\text{ = }\frac{23}{2}\text{inches} \end{gathered}[/tex]Yousef cuts the piece of paper into two pieces of paper of equal widths:
Let each of the smaller pieces have a width of w
W = 2w (since the smaller pieces have equal widths)
[tex]\begin{gathered} \frac{23}{2}=\text{ 2w} \\ 23\text{ = 4w} \\ \frac{23}{4}=\text{ w} \\ w\text{ = 5}\frac{3}{4}in \end{gathered}[/tex]
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