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For f(x)=2^x, find for for f(5) and f (-6)

Sagot :

Exponentials

It order to find f(5) and f ( -6 ) we just replace x on the equation with

x = 5 and x = -6

In the first case, x = 5

[tex]\begin{gathered} f(x)=2^x \\ f(5)=2^5 \\ =2\cdot2\cdot2\cdot2\cdot2 \\ =32 \end{gathered}[/tex]

In the second case, x = -6

[tex]\begin{gathered} f(x)=2^x \\ f(-6)=2^{-6} \\ =\frac{1}{2^6} \\ =\frac{1}{2\cdot2\cdot2\cdot2\cdot2\cdot2} \\ =\frac{1}{64} \end{gathered}[/tex]

Answer: f(5) = 32 and f(-6) = 1/64