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please help me with these questions (lesson 2.06 and below)

Please Help Me With These Questions Lesson 206 And Below class=

Sagot :

N 2.06

we have the function

[tex]H(x)=-2\sqrt[3]{x}+1[/tex]

For each value of x, substitute in the given function to obtain the value of H(x)

so

For x=-8

substitute

[tex]\begin{gathered} H(x)=-2\sqrt[3]{-8}+1 \\ H(x)=-2(-2)+1 \\ H(x)=5 \end{gathered}[/tex]

For x=0

[tex]\begin{gathered} H(x)=-2\sqrt[3]{0}+1 \\ H(x)=-2(0)+1 \\ H(x)=1 \end{gathered}[/tex]

For x=1

[tex]\begin{gathered} H(x)=-2\sqrt[3]{1}+1 \\ H(x)=-2(1)+1 \\ H(x)=-1 \end{gathered}[/tex]

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