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Sagot :
Answer
11 gallons of the 25% alcohol is required for the mixture.
4 gallons of the 10% alcohol is required for the mixture.
Explanation
Let the number of gallons of 25% alcohol required be x
Let the number of gallons of 10% alcohol required be y
The total amount of gallons required is 15 gallons. In mathematical terms,
x + y = 15
The alcohol content of the 15 gallons is to be 21%.
21% of 15 gallons = 3.15 gallons
From the first statements,
Let the number of gallons of 25% alcohol required be x
Let the number of gallons of 10% alcohol required be y
25% of x gallons = 0.25x gallons
10% of y gallons = 0.10y gallons
0.25x + 0.10y = 3.15
We can then bring these two equations together to solve simultaneously
x + y = 15
0.25x + 0.10y = 3.15
Solving this simultaneously with the calculator, we obtain
x = 11 gallons
y = 4 gallons
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