Answered

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The remains of an ancient ball court include a rectangular playing alley with a perimeter of about 18m. The length of the alley is two times the width. Find the length and the width of the playing alley.The width is ? m and the length is ? m.

Sagot :

Given:

Perimeter = 18 m

The formula for the perimeter of a rectangle is:

[tex]P=2l+2w[/tex]

Where:

l = lenght

w = width

In this case, we have that:

l = 2w

Therefore, we substitute the values in the formula:

[tex]\begin{gathered} P=2l+2w \\ 18=2(2w)+2w \end{gathered}[/tex]

And solve for w:

[tex]\begin{gathered} 18=4w+2w \\ 18=6w \\ \frac{18}{6}=\frac{6w}{6} \\ w=3 \end{gathered}[/tex]

For the length:

[tex]l=2w=2(3)=6[/tex]

Answer:

The width is 3 m

The length is 6 m

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