Answer:
The equation that represents the perpendicular line is;
[tex]2y-5x=-10[/tex]Explanation:
We want to find the equation of a line perpendicular to the line;
[tex]y=-\frac{2}{5}x+5[/tex]Recall that for two lines to be perpendicular to each other, their slope must be a negative reciprocal of one another.
[tex]m_1.m_2=-1_{}_{}[/tex]so;
[tex]m_2=-\frac{1}{m_1}[/tex]For the given equation, the slope of the given line is;
[tex]m_1=-\frac{2}{5}[/tex]To get the slope of the perpendicular line, let us substitute m1 to the equation above;
[tex]\begin{gathered} m_2=-\frac{1}{m_1} \\ m_2=-\frac{1}{(-\frac{2}{5})_{}} \\ m_2=\frac{5}{2_{}} \end{gathered}[/tex]So, the equation of the perpendicular line would be of the form;
[tex]\begin{gathered} y=m_2x+c \\ y=\frac{5}{2}x+c \\ mu\text{ltiply through by 2} \\ 2y=5x+c \\ 2y-5x=c \end{gathered}[/tex]The equation of the perpendicular line will be of the form;
[tex]2y-5x=c[/tex]Where c is a constant;
From the options, the only equation that is similar to the derived equation is;
[tex]2y-5x=-10[/tex]Therefore, the equation of the perpendicular line is;
[tex]2y-5x=-10[/tex]