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Sagot :
Answer:
0.0899 moles of oxygen (O2).
Explanation:
What is given?
Mass of sodium oxide (Na2O) = 11.15 g.
Molar mass of Na2O = 62 g/mol.
Step-by-step solution:
First, let's state the balanced chemical equation:
[tex]4Na+O_2\rightarrow2Na_2O.[/tex]Let's calculate the moles of Na2O that are in 11.15 g of Na2O, using its molar mass:
[tex]11.15\text{ g Na}_2O\cdot\frac{1\text{ mol Na}_2O}{62\text{ g Na}_2O}=0.1798\text{ moles Na}_2O.[/tex]Now that we have the moles of Na2O, let's do the stoichiometry: you can see in the chemical equation that 1 mol of oxygen (O2) reacted produces 2 moles of Na2O, so by doing a rule of three based on this data, the calculation will look like this:
[tex]0.1798\text{ moles Na}_2O\cdot\frac{1\text{ mol O}_2}{2\text{ moles Na}_2O}=0.0899\text{ moles O}_2.[/tex]The answer is that we need 0.0899 moles of oxygen (O2) to produce 11.15 g of sodium oxide.
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