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In a bike race, a sport person starts his bike from rest and maintains a constant acceleration of 3 m/s2 for 8 seconds, and then a constant acceleration of 2 m/s2 for another 8 seconds. Determine the acquired velocity of the bike.

Sagot :

Answer:

40 m/s

Explanation:

First, we need to calculate the velocity after 8 seconds, so we will use the following equation:

vā‚‚ = vā‚ + at

Where vā‚ is the initial velocity, so vā‚ = 0 m/s, a is the acceleration a = 3 m/sĀ² and t is the time, so t = 8s. Replacing the values, we get:

vā‚‚ = 0 m/s + (3 m/sĀ²)(8s)

vā‚‚ = 0 m/s + 24 m/s

vā‚‚ = 24 m/s

Then, it accelerates for another 8 seconds with a = 2 m/sĀ², so the acquired velocity vā‚ƒ is equal to:

vā‚ƒ = vā‚‚ + at

vā‚ƒ = 24 m/s + (2 m/sĀ²)(8 s)

vā‚ƒ = 24 m/s + 16 m/s

vā‚ƒ = 40 m/s

Therefore, the acquired velocity of the bike is 40 m/s

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