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Given that4 NH3 (g) + 5 O2(g) > 4 NO(g) + 6 H2O(g)If 8.20 moles of NH3 react with sufficient oxygen, how many moles of water should form?1. 6.11 moles2. 12.0 moles3. 22.0 moles4. 8.25 moles5. 15.1 moles

Sagot :

Answer:

[tex]12.3\text{ moles}[/tex]

Explanation:

Here, we want to get the number of moles of water that would form

From the equation of reaction, 4 moles of ammonia produced 6 moles of water

However, 8.2 moles of ammonia will produce x moles of water

To get the value of x, we have it that:

[tex]\begin{gathered} \text{ 4 }\times x\text{ = 8.2}\times\text{ 6} \\ x\text{ = }\frac{8.2\text{ }\times6}{4} \\ \text{ x= 12.3 moles} \end{gathered}[/tex]

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