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PQR is a right triangle. If PQ=8, what is PR?

PQR Is A Right Triangle If PQ8 What Is PR class=

Sagot :

Sine formula

[tex]\sin (angle)=\frac{\text{ opposite side}}{\text{ hypotenuse}}[/tex]

Considering angle Q = 60°, the opposite side is PR, and the hypotenuse is PQ = 8. Substituting this information into the formula, we get:

[tex]\begin{gathered} \sin (m\angle Q)=\frac{PR}{PQ} \\ \sin (60\degree)=\frac{PR}{8} \\ \frac{\sqrt[]{3}}{2}=\frac{PR}{8} \\ \frac{\sqrt[]{3}}{2}\cdot8=PR \\ 4\sqrt[]{3}=PR \end{gathered}[/tex]

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