Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Find the equation of a line perpendicular to the given line and pass through the given point. Write equation in slope-intercept form Line y= -4/5x + 2 point, (8,9) Graph

Sagot :

ANSWER

Equation:

[tex]y=\frac{5}{4}x-1[/tex]

Graph:

The red line is the graph of the given line and the green line is the graph of the perpendicular line passing through (8, 9).

EXPLANATION

The equation of the line is given in the slope-intercept form,

[tex]y=-\frac{4}{5}x+2[/tex]

The slope is -4/5 and the y-intercept is 2.

Two lines are perpendicular if their slopes are opposite reciprocals of each other. Therefore, a perpendicular line to the given line has a slope of 5/4,

[tex]y=\frac{5}{4}x+b[/tex]

There is an infinite number of perpendicular lines, but there is only one that passes through the point (8, 9). Replace x and y with the coordinates of this point in the equation above,

[tex]9=\frac{5}{4}\cdot8+b[/tex]

And solve for b,

[tex]\begin{gathered} 9=5\cdot2+b \\ 9=10+b \\ 9-10=b \\ -1=b \end{gathered}[/tex]

Hence, the equation of the perpendicular line is,

[tex]y=\frac{5}{4}x-1[/tex]

View image AvaraeU345552