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Sagot :
Write an equation in general form of the circle with the given properties.
Ends of diameter at (5,7) and (-5,-7)
we have that
the equation of the circle is
(x-h)^2+(y-k)^2=r^2
where (h,k) is the center and r is the radius
step 1
Find the center
Remember that
The center of the circle is the midpoint of diameter
so
[tex]\begin{gathered} (h,k)=(\frac{5-5}{2},\frac{7-7}{2}) \\ (h,k)=(0,0) \end{gathered}[/tex]the center is the origin
step 2
Find the radius
Find the diameter
calculate the distance between two points
[tex]\begin{gathered} d=\sqrt[\square]{(-7-7)^2+(-5-5)^2} \\ d=\sqrt[\square]{(-14)^2+(-10)^2} \\ d=\sqrt[\square]{296} \end{gathered}[/tex]simplify
[tex]D=\sqrt[\square]{296}=2\sqrt[\square]{74}[/tex]the radius is half the diameter
so
r=2√74/2=√74
step 3
the equation iof the circle is
x^2+y^2=(√74)^2
x^2+y^2=74
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