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Sagot :
10x - 6 = 3 ( x + 1/2)
To find the value of x that make the equation true, we need to solve for x
open the parenthesis
10x - 6 = 3x + 3/2
collect like term
10x - 3x = 3/2 + 6
[tex]7x\text{ =}\frac{3+12}{2}[/tex][tex]7x\text{ =}\frac{15}{2}[/tex]Multiply both-side of the equation by 1/7
[tex]x\text{ =}\frac{15}{2}\times\frac{1}{7}[/tex][tex]x=\frac{15}{14}[/tex]
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