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Sagot :
Given the following:
plane A flies 4375 miles
plane B flies 4550 miles
plane B is flying 35 mph more than plan A.
We are should find the amount of time it takes each plane to atravel their respective distances.
The time equation is:
4375 = 4550
x x + 35
Lets cross multipy
4375(x + 35) = x(4550)
4375x + 153125 = 4550x
153125 = 4550x - 4375x
153125 = 175x
175x = 153125
x = 153125/175
x = 875
x is the speed of plane A
Speed of plane B = 875 + 35 = 910
The amount of time plane A will use is = 4375/875 = 5
The amount of time plane B will use is = 4550/910 = 5
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