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Plane a flies 4375 miles in the same amount of time

Plane A Flies 4375 Miles In The Same Amount Of Time class=

Sagot :

Given the following:

plane A flies 4375 miles

plane B flies 4550 miles

plane B is flying 35 mph more than plan A.

We are should find the amount of time it takes each plane to atravel their respective distances.

The time equation is:

4375 = 4550

x x + 35

Lets cross multipy

4375(x + 35) = x(4550)

4375x + 153125 = 4550x

153125 = 4550x - 4375x

153125 = 175x

175x = 153125

x = 153125/175

x = 875

x is the speed of plane A

Speed of plane B = 875 + 35 = 910

The amount of time plane A will use is = 4375/875 = 5

The amount of time plane B will use is = 4550/910 = 5

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